#### Answer

{$\pm 8$}

#### Work Step by Step

Given: $2x^2-3=125$
This implies $2x^2-128=0$
Take the common terms out.
$2(x^2-64)=0$
This can be written as: $(x^2-8^2)=0$
$(x+8)(x-8)=0$
Thus, $x=\pm 8 $
Hence, $x=${$\pm 8$}

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Published by
Pearson

ISBN 10:
0-13417-894-7

ISBN 13:
978-0-13417-894-3

{$\pm 8$}

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